Relative Equilibrium of Liquids

Learning Objectives

  • Explain relative equilibrium in a non-inertial container frame and define effective gravity for translational acceleration.
  • Determine pressure gradients and free-surface slope under horizontal, vertical, and combined linear acceleration.
  • Distinguish no-spill, spill, and loss-of-contact regimes before applying rectangular-tank formulas.
  • Explain the free-fall limit without confusing zero pressure gradient with zero absolute pressure.
  • Derive the forced-vortex pressure gradients and parabolic free surface for rigid-body rotation.
  • Apply volume conservation, incipient-spill, angular-speed conversion, and rotating-pressure-field relations with explicit coordinate conventions.
  • Recognize when open-tank geometry, dry-core formation, confinement, cavitation, or other physical limits invalidate the elementary idealization.

Relative Equilibrium

A liquid is in relative equilibrium when, after transients decay, it has no motion relative to its translating or rotating container. In the container frame the liquid behaves as a rigid body, so hydrostatic-type pressure relations can be written using the appropriate effective body-force field.

Effective Gravity, g⃗eff\vec g_{\text{eff}}

For a container translating with acceleration a⃗0\vec a_0, effective gravity is the gravitational acceleration vector combined with the opposite inertial acceleration perceived in the accelerating container frame.

Effective Gravity for Translational Acceleration

Defines the effective body-force acceleration in a frame attached to a translating container.

g⃗eff=g⃗−a⃗0\vec g_{\text{eff}}=\vec g-\vec a_0

Variables

SymbolDescriptionUnit
g⃗eff\vec g_{\text{eff}}Effective gravity vector in the container framem/s2m/s^2
g⃗\vec gTrue gravitational acceleration vectorm/s2m/s^2
a⃗0\vec a_0Container translational acceleration vectorm/s2m/s^2

Pressure Gradient in Translational Relative Equilibrium

Relates static pressure gradient in the container frame to effective gravity.

∇p=ρg⃗eff\nabla p=\rho\vec g_{\text{eff}}

Variables

SymbolDescriptionUnit
ppFluid pressurePa
ρ\rhoFluid densitykg/m3kg/m^3
g⃗eff\vec g_{\text{eff}}Effective gravity vectorm/s2m/s^2
Effective gravity in an accelerating frameGravity and frame acceleration define the effective body-force direction.gravityframe accelerationeffective gravity

Effective gravity in an accelerating frame

Gravity and frame acceleration define the effective body-force direction.

Free Surfaces Are Equipressure Surfaces

For an open liquid free surface exposed to one atmosphere, pressure is constant along the surface. Its tangent direction is therefore perpendicular to ∇p\nabla p and to g⃗eff\vec g_{\text{eff}} whenever g⃗eff≠0\vec g_{\text{eff}}\ne0.

Horizontal Acceleration

Let xx be positive in the direction of a constant horizontal container acceleration axa_x, and let zz be positive upward. Effective gravity then has a component opposite the acceleration. Pressure decreases in the positive xx direction, so the free surface rises at the rear and falls at the front.

Free surface under horizontal accelerationThe free surface tilts normal to effective gravity.accelerationsurface slopeeffective gravity

Free surface under horizontal acceleration

The free surface tilts normal to effective gravity.

Pressure Gradients under Horizontal Acceleration

Gives the horizontal and vertical pressure gradients for constant horizontal acceleration.

∂p∂x=−ρax,∂p∂z=−ρg\frac{\partial p}{\partial x}=-\rho a_x, \qquad \frac{\partial p}{\partial z}=-\rho g

Variables

SymbolDescriptionUnit
axa_xHorizontal acceleration magnitude in the positive x directionm/s2m/s^2
xxHorizontal coordinatem
zzVertical coordinate positive upwardm

Free-Surface Slope under Horizontal Acceleration

Determines the plane free-surface slope while the liquid remains in contact with the tank and before spilling changes the volume.

dzdx=−axg\frac{dz}{dx}=-\frac{a_x}{g}tan⁡θ=∣ax∣g\tan\theta=\frac{|a_x|}{g}

Variables

SymbolDescriptionUnit
θ\thetaMagnitude of free-surface angle from horizontaldegrees or rad
axa_xHorizontal container accelerationm/s2m/s^2
ggGravitational acceleration magnitudem/s2m/s^2

End-to-End Surface Difference in a Rectangular Tank

Relates horizontal acceleration to free-surface elevation difference over tank length L.

Δh=∣ax∣Lg\Delta h=\frac{|a_x|L}{g}

Variables

SymbolDescriptionUnit
Δh\Delta hDifference in free-surface elevation between the tank endsm
LLInside tank length measured parallel to the horizontal accelerationm

No-Spill End Depths

For a rectangular tank with initial uniform depth h0h_0 and no volume loss, the mean depth remains h0h_0. If the plane free surface remains inside the tank and liquid contact is maintained, the raised and lowered end depths are

hhigh=h0+Δh2,hlow=h0−Δh2h_{\text{high}}=h_0+\frac{\Delta h}{2}, \qquad h_{\text{low}}=h_0-\frac{\Delta h}{2}

These formulas must not be continued after the raised end crosses the rim or the lowered end predicts a negative depth.

Check Geometry before Using No-Spill Formulas

First compare hhighh_{\text{high}} with tank height and hlowh_{\text{low}} with zero. If the high side reaches the rim, liquid spills and the remaining volume must be recomputed with the rim as a boundary. If the low-side depth reaches zero, the liquid loses contact with part of the tank bottom and a different geometric regime begins.

Vertical Acceleration

A purely vertical acceleration leaves the free surface horizontal while changing the effective downward acceleration. Upward container acceleration increases apparent gravity to g+avg+a_v. Downward acceleration less than gg reduces apparent gravity to g−avg-a_v.

Vertical acceleration and pressure gradientVertical frame acceleration changes effective gravity and pressure gradient.vertical accelerationeffective gravitypressure gradient

Vertical acceleration and pressure gradient

Vertical frame acceleration changes effective gravity and pressure gradient.

Pressure under Upward Acceleration

Computes gage pressure at depth h below an open free surface during uniform upward acceleration.

pg=ρ(g+av)hp_g=\rho(g+a_v)h

Variables

SymbolDescriptionUnit
pgp_gGage pressure relative to the open free surfacePa
ava_vUpward container acceleration magnitudem/s2m/s^2
hhDepth below the free surfacem

Pressure under Downward Acceleration

Computes gage pressure at depth h while downward container acceleration remains less than g and contact is maintained.

pg=ρ(g−av)hp_g=\rho(g-a_v)h

Variables

SymbolDescriptionUnit
pgp_gGage pressure relative to the open free surfacePa
ava_vDownward container acceleration magnitudem/s2m/s^2
hhDepth below the free surfacem

Free Fall Means Zero Pressure Gradient, Not Zero Absolute Pressure

At downward acceleration av=ga_v=g, g⃗eff=0\vec g_{\text{eff}}=0 and therefore ∇p=0\nabla p=0. Pressure becomes spatially uniform within a connected liquid under the idealization. Its value is still set by the applicable boundary or confinement condition. If a connected boundary fixes pressure at 95 kPa95\ \text{kPa} absolute, the ideal free-falling liquid is uniformly at 95 kPa95\ \text{kPa} absolute—not at zero absolute pressure. An open atmospheric boundary would similarly set the uniform liquid pressure to atmospheric pressure while the boundary remains physically connected.

Downward Acceleration Greater than Gravity

When a nominally open container accelerates downward faster than gg, effective gravity points upward in the container frame. The ordinary assumption that liquid remains on the bottom with a conventional upper free surface may fail. Use the simple formula only when confinement and contact conditions actually support the assumed geometry.

Combined Horizontal and Vertical Acceleration

Determines free-surface angle using the magnitude of the effective downward component.

tan⁡θ=∣ax∣geff\tan\theta=\frac{|a_x|}{g_{\text{eff}}}

Variables

SymbolDescriptionUnit
geffg_{\text{eff}}Positive effective downward acceleration, equal to g+a_v upward or g-a_v downward while contact is maintainedm/s2m/s^2
axa_xHorizontal acceleration magnitudem/s2m/s^2
θ\thetaFree-surface angle magnitudedegrees or rad

Interactive Relative-Equilibrium Exploration

Use the simulation to vary translational acceleration and rotation. Treat the display as a visualization of the governing equations and separately verify whether the selected state would spill, uncover the bottom, or violate the pressure assumptions.

Relative Equilibrium Simulator

Learning objective: Observe how translational acceleration or rigid-body rotation changes effective gravity, free-surface geometry, and the pressure field.

Open tank: 2.0 m long, 1.8 m high, initially filled to 1.0 m.

Hydraulics interactive visualizationObserve how translational acceleration or rigid-body rotation changes effective gravity, free-surface geometry, and the pressure field.initial level

Positive is upward. At −9.81 m/s² the tank is in free fall.

Effective downward gravity9.81 m/s²
Surface angle0.00°
End-to-end elevation difference0.000 m
Left / right depth1.000 / 1.000 m

The free surface is perpendicular to effective gravity. It falls in the direction of horizontal acceleration, with∣dz/dx∣=∣ax∣/(g+av)\left|dz/dx\right|=|a_x|/(g+a_v).

Forced Vortex

A forced vortex is rigid-body rotation of a liquid at a common angular velocity after transients decay under an imposed rotating container or equivalent forcing.

Pressure Gradients in Rigid-Body Rotation

Gives radial and vertical pressure gradients for rotation about a vertical axis.

∂p∂r=ρω2r,∂p∂z=−ρg\frac{\partial p}{\partial r}=\rho\omega^2r, \qquad \frac{\partial p}{\partial z}=-\rho g

Variables

SymbolDescriptionUnit
rrRadial distance from the rotation axism
zzVertical coordinate positive upwardm
ω\omegaAngular velocityrad/s

Parabolic Free Surface

In rigid-body rotation about a vertical axis, an open liquid free surface is a paraboloid of revolution because constant-pressure points satisfy a quadratic relation between elevation and radius.

Parabolic Free-Surface Equation

Gives free-surface elevation relative to the vertex on the rotation axis.

z−z0=ω2r22gz-z_0=\frac{\omega^2r^2}{2g}

Variables

SymbolDescriptionUnit
zzFree-surface elevation at radius rm
z0z_0Free-surface elevation at the axism
rrRadial coordinatem
ω\omegaAngular velocityrad/s
Forced-vortex free surfaceRigid-body rotation produces a parabolic free surface.rotation axisangular speedparabolic surface

Forced-vortex free surface

Rigid-body rotation produces a parabolic free surface.

Center-to-Wall Elevation Difference

Evaluates the free-surface elevation difference from axis to wall in a cylindrical tank.

Δh=ω2R22g\Delta h=\frac{\omega^2R^2}{2g}

Variables

SymbolDescriptionUnit
Δh\Delta hWall elevation minus center elevationm
RRTank radiusm
ω\omegaAngular velocityrad/s

Interactive 3D Relative Equilibrium & Rotating Paraboloid

Manipulate linear acceleration or rotating angular velocity in 3D. Observe the 3D paraboloid of revolution, verify volume conservation (hwall=h0+Δh/2h_{\text{wall}} = h_0 + \Delta h / 2 and hcenter=h0−Δh/2h_{\text{center}} = h_0 - \Delta h / 2), and test for incipient spillover.

Relative Equilibrium Fluid Surfaces 3D

Interactive 3D free surfaces, isobaric layers, linear translation tilt, and centrifugal paraboloid of revolution.

Loading 3D Relative Equilibrium Simulation…

Linear Acceleration Parameters

Horizontal Accel (axa_x)2.5 m/s²
Vertical Accel (aza_z)0.0 m/s²
Rest Water Depth (d0d_0)1.20 m
Tank Length (L=2RL = 2R)2.40 m
Surface Tilt θ\theta14.3°
Rear Wall Depth1.51 m
Front Wall Depth0.89 m
Effective Gravity9.81 m/s²
Spill StatusContained
Floor ExposureFully Submerged

Angular-Speed Conversion

Converts rotational speed N in revolutions per minute to angular velocity.

ω=2πN60\omega=\frac{2\pi N}{60}

Variables

SymbolDescriptionUnit
NNRotational speedrpm
ω\omegaAngular velocityrad/s

No-Spill Volume Conservation in a Cylindrical Tank

While the paraboloidal surface remains entirely within the tank and the vertex stays above the bottom, volume conservation keeps the plan-area average liquid level equal to the original depth. Because the area-average of r2r^2 over a circle is R2/2R^2/2, the center falls by Δh/2\Delta h/2 and the wall rises by Δh/2\Delta h/2.

No-Spill Center and Wall Depths

Relates initial depth to the axis and wall depths for a fully wetted rotating cylindrical tank before spilling.

hc=h0−Δh2,hw=h0+Δh2h_c=h_0-\frac{\Delta h}{2}, \qquad h_w=h_0+\frac{\Delta h}{2}

Variables

SymbolDescriptionUnit
hch_cLiquid depth at the rotation axism
hwh_wLiquid depth at the tank wallm
h0h_0Initial uniform liquid depthm

Spill and Dry-Core Regimes Must Be Treated Separately

If hwh_w reaches the rim, further rotation causes spillage and the wall elevation becomes constrained by tank height; remaining volume must be recomputed. If the calculated axis depth hch_c reaches zero, the paraboloid intersects the tank bottom and a dry central region can form. The simple symmetric rise/drop relation no longer applies beyond either transition.

Rotating-Liquid Pressure Field with Upward-Positive Elevation

Gives gage pressure relative to an atmospheric free-surface vertex at r=0, z=0.

pg=ρ(ω2r22−gz)p_g=\rho\left(\frac{\omega^2r^2}{2}-gz\right)

Variables

SymbolDescriptionUnit
pgp_gGage pressure relative to the atmospheric vertex pressurePa
rrRadial coordinatem
zzElevation from the vertex, positive upwardm
ω\omegaAngular velocityrad/s

Keep the Vertical Coordinate Sign Consistent

With upward-positive zz, points below the vertex have negative zz, so the term −gz-gz increases pressure. If a downward-positive depth zdz_d is used instead, write pg=ρ(ω2r2/2+gzd)p_g=\rho(\omega^2r^2/2+gz_d). Mixing the two conventions reverses the hydrostatic contribution.

Closed Rotating Tank Pressure Field

A completely filled closed rotating tank has no atmospheric free surface to set the integration constant. The same radial and vertical pressure gradients apply, but one known pressure at a specified location is required to determine absolute pressure everywhere else.

Check Minimum Absolute Pressure in Closed Rotation

After determining the pressure field in a closed rotating liquid, compare the minimum absolute pressure with the liquid vapor pressure at the relevant temperature. If the predicted pressure drops too low, the assumed single-phase liquid field can fail through cavitation or vapor-pocket formation.

Engineering Applicability Checks

Key Takeaways
  • Relative equilibrium replaces ordinary gravity with an effective body-force field in the accelerating container frame.
  • A horizontally accelerating open liquid develops a plane free surface that rises opposite the acceleration direction.
  • Vertical acceleration changes apparent gravity but does not tilt the free surface.
  • Free fall eliminates the hydrostatic pressure gradient; it does not universally set absolute pressure to zero.
  • No-spill formulas are valid only while the predicted surface remains within the tank and liquid contact is maintained.
  • Forced-vortex rotation produces a paraboloidal free surface and an outward radial pressure increase proportional to ρω2r\rho\omega^2r.
  • Cylindrical no-spill volume conservation gives equal center drop and wall rise of Δh/2\Delta h/2 only while the bottom remains fully wetted.
  • Spillage, dry-core formation, confinement, coordinate choice, and vapor-pressure limits must be checked before accepting an ideal solution.
  • Closed rotating tanks require one pressure reference point because there is no atmospheric free surface to fix the integration constant.