Example

Problem 1: Continuity through a Converging Pipe

Water flows through a pipe that contracts from 200 mm200\text{ mm} diameter to 100 mm100\text{ mm}. The upstream velocity is 2.0 m/s2.0\text{ m/s}. Determine the discharge and downstream velocity.

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Example

Problem 2: Flow Division at a Junction

A pipe carries 0.100 m3/s0.100\text{ m}^3/\text{s} and divides into two branches. Branch 1 has diameter 150 mm150\text{ mm} and velocity 2.0 m/s2.0\text{ m/s}. Branch 2 has diameter 200 mm200\text{ mm}. Determine the flow and velocity in Branch 2.

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Example

Problem 3: Compressible Mass Continuity

Air enters a duct with density 1.20 kg/m31.20\text{ kg/m}^3, area 0.50 m20.50\text{ m}^2, and velocity 10 m/s10\text{ m/s}. It exits where density is 0.90 kg/m30.90\text{ kg/m}^3 and area is 0.30 m20.30\text{ m}^2. Determine mass flow rate and exit velocity.

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Example

Problem 4: Acceleration from a Two-Dimensional Velocity Field

A steady velocity field is

V=(2xy)i+(x2y2)j\mathbf V=(2xy)\mathbf i+(x^2-y^2)\mathbf j

Determine acceleration at (x,y)=(1,2)(x,y)=(1,2).

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Example

Problem 5: Local and Convective Acceleration

A one-dimensional velocity field is u=x(1+2t)u=x(1+2t), where xx is in meters and tt in seconds. Determine local, convective, and total acceleration at x=2 mx=2\text{ m} and t=1 st=1\text{ s}.

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Example

Problem 6: Velocity and Flow from a Streamfunction

A two-dimensional incompressible flow has streamfunction ψ=3xy\psi=3xy in m2/s\text{m}^2/\text{s}. Find the velocity at (2,1)(2,1) and the discharge per unit width between streamlines ψ=3\psi=3 and ψ=12\psi=12.

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Example

Problem 7: Incompressibility and Irrotationality Check

For the velocity field u=4xu=4x and v=4yv=-4y, determine whether the two-dimensional flow is incompressible and irrotational.

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Example

Problem 8: Unsteady Storage in a Tank

A vertical tank has constant plan area 10 m210\text{ m}^2. Water enters at 0.080 m3/s0.080\text{ m}^3/\text{s} and leaves at 0.030 m3/s0.030\text{ m}^3/\text{s}. Determine the water-level rise rate and the rise after 5 min5\text{ min}.

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