Example

Problem 1: Two Pipes in Series

Pipe 1 has L1=100 mL_1=100\text{ m}, D1=0.20 mD_1=0.20\text{ m}, and f1=0.020f_1=0.020. Pipe 2 has L2=200 mL_2=200\text{ m}, D2=0.30 mD_2=0.30\text{ m}, and f2=0.015f_2=0.015. Both carry Q=0.100 m3/sQ=0.100\text{ m}^3/\text{s}. Determine total friction head loss.

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Example

Problem 2: Equivalent Diameter for Series Pipes

Replace the series system in Problem 1 with one 300 m300\text{ m} long pipe carrying the same discharge with f=0.020f=0.020 and the same 6.184 m6.184\text{ m} head loss. Estimate the equivalent diameter.

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Example

Problem 3: Flow Split between Parallel Pipes

Two pipes connect the same nodes and carry a total of 0.100 m3/s0.100\text{ m}^3/\text{s}. Pipe 1: L=200 mL=200\text{ m}, D=0.20 mD=0.20\text{ m}, f=0.020f=0.020. Pipe 2: L=300 mL=300\text{ m}, D=0.25 mD=0.25\text{ m}, f=0.022f=0.022. Determine branch flows.

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Example

Problem 4: Three-Reservoir Junction

Reservoir heads are H1=100 mH_1=100\text{ m}, H2=80 mH_2=80\text{ m}, and H3=60 mH_3=60\text{ m}. Their pipes connect to one junction and have resistance coefficients R1=2000R_1=2000, R2=1000R_2=1000, and R3=3000R_3=3000 in h=RQ2h=RQ^2. Determine junction head and flow directions.

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Example

Problem 5: One Hardy Cross Loop Correction

For one loop, take clockwise flow as positive. Three pipe terms have (r,Q)(r,Q) values (500,0.040)(500,0.040), (800,0.020)(800,0.020), and (300,0.010)(300,-0.010), with head loss h=rQQh=rQ|Q|. Determine the first Hardy Cross correction.

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Example

Problem 6: Equivalent Resistance of Parallel Pipes

Two parallel branches obey h=RQ2h=RQ^2 with R1=1000R_1=1000 and R2=4000R_2=4000. Determine the equivalent resistance and branch flows when total flow is 0.090 m3/s0.090\text{ m}^3/\text{s}.

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Example

Problem 7: Rapid and Slow Valve Closure

A 500 m500\text{ m} pipeline carries water at 2.0 m/s2.0\text{ m/s}. Wave celerity is 1000 m/s1000\text{ m/s}. Compare pressure rise for valve closure in (a) 0.60 s0.60\text{ s} and (b) 2.0 s2.0\text{ s}. Use ρ=1000 kg/m3\rho=1000\text{ kg/m}^3.

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Example

Problem 8: Pump and System Operating Point

A pump curve and system curve use discharge QQ in L/s\text{L/s}:

Hp=500.020Q2H_p=50-0.020Q^2Hs=10+0.030Q2H_s=10+0.030Q^2

Determine operating discharge and head.

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