Problem 1: Manning Discharge in a Rectangular Channel

A rectangular concrete channel is 3.00 m3.00\text{ m} wide and carries water 1.50 m1.50\text{ m} deep. The friction slope is Sf=0.00100S_f=0.00100 and Manning n=0.0150n=0.0150. Determine the uniform discharge.

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Problem 2: Normal Depth by Bracketing

A 4.00 m4.00\text{ m} wide rectangular channel must carry 10.0 m3/s10.0\text{ m}^3/\text{s} with n=0.0150n=0.0150 and Sf=0.000800S_f=0.000800. Determine the normal depth and verify the result.

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Problem 3: Trapezoidal-Channel Capacity

A trapezoidal channel has bottom width b=2.00 mb=2.00\text{ m}, side slope m=1.50m=1.50, depth y=1.20 my=1.20\text{ m}, n=0.0250n=0.0250, and Sf=0.00150S_f=0.00150. Determine discharge.

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Problem 4: Required Uniform-Flow Slope

A rectangular channel is 5.00 m5.00\text{ m} wide and 1.00 m1.00\text{ m} deep and must carry 12.0 m3/s12.0\text{ m}^3/\text{s}. Use Manning n=0.0180n=0.0180. Determine the required friction slope.

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Problem 5: Back-Calculate Manning Roughness from Field Data

A channel section has A=4.00 m2A=4.00\text{ m}^2, R=0.800 mR=0.800\text{ m}, measured discharge Q=8.00 m3/sQ=8.00\text{ m}^3/\text{s}, and energy slope Sf=0.00160S_f=0.00160. Estimate the effective Manning coefficient represented by the observation.

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Problem 6: Most Efficient Rectangular Section

Determine the hydraulically efficient rectangular dimensions for a required flow area of 12.0 m212.0\text{ m}^2.

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Problem 7: Most Efficient Trapezoidal Section

A hydraulically efficient trapezoidal channel must have area 20.0 m220.0\text{ m}^2 and side slopes 1H:1V1\text{H}:1\text{V}. Determine depth and bottom width.

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Problem 8: Half-Full Circular Conduit versus Full Gravity Flow

A circular conduit has diameter D=1.20 mD=1.20\text{ m}, n=0.0130n=0.0130, and Sf=0.00200S_f=0.00200. Determine the half-full discharge and compare it with the nominal full-flow gravity discharge using Manning's equation.

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Problem 9: Circular Conduit near Maximum-Discharge Depth

For the same 1.20 m1.20\text{ m} conduit, evaluate Manning discharge at y/D=0.940y/D=0.940 using n=0.0130n=0.0130 and Sf=0.00200S_f=0.00200, then compare it with the nominal full-flow discharge.

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Problem 10: Compound-Section Conveyance

A main-channel subsection has A1=20.0 m2A_1=20.0\text{ m}^2, R1=1.50 mR_1=1.50\text{ m}, and n1=0.0300n_1=0.0300. An adjacent floodplain subsection has A2=30.0 m2A_2=30.0\text{ m}^2, R2=0.500 mR_2=0.500\text{ m}, and n2=0.0600n_2=0.0600. The common energy slope is Sf=0.00100S_f=0.00100. Estimate total discharge by summing conveyances.

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