Back to Statics Of Rigid Bodies repository
Friction2D

Sliding versus overturning

Distinguish actual static-friction demand from limiting friction in blocks, ladders, wedges, and belt systems.

Open the complete lesson

Advanced engineering statics simulation

Statics Friction Simulation Suite

Five distinct dry-friction models with explicit assumptions and scenario-specific free-body diagrams.

Compare the horizontal force required for sliding with the force required for first tipping about the base edge.

Weight
120 N
N
20–500

Drag for exploration or enter an exact value. Press Enter to apply and Escape to restore.

Static friction coefficient
0.45
0.05–1.00

Drag for exploration or enter an exact value. Press Enter to apply and Escape to restore.

Base width
3.0 m
m
0.5–5.0

Drag for exploration or enter an exact value. Press Enter to apply and Escape to restore.

Horizontal-load height
2.0 m
m
0.2–5.0

Drag for exploration or enter an exact value. Press Enter to apply and Escape to restore.

Calculated statesliding
WPFtipping edge
Sliding threshold
54.00 N
Tipping threshold
90.00 N
First motion
sliding
Governing force
54.00 N
Pslide=μsW,Ptip=Wb2hP_{slide}=\mu_sW,\qquad P_{tip}=\frac{Wb}{2h}

Static friction matches equilibrium demand until its limiting value is reached.

Concept question: Predict the governing force or friction demand.

Model scope and verification

Scope: Educational rigid-body statics model using the selected geometry, stated idealizations, and displayed SI units.

Acceptance check: Check the governing equilibrium, compatibility, geometry, or limiting-condition statement before accepting the numerical result.

Related simulations

Block on an inclined planeRough ladder against a wallRough-interface wedgeBelt-friction explorer