Normal Stress Visualizer

50 kN
50 kN
Area (AA): 314.2 mm²
Calculated Stress (σ\sigma)
159.15 MPa
Adjust the force and the radius of the circular cross-section to see how they affect the normal stress. Notice that increasing the area (radius) decreases the stress, while increasing the force increases the stress.

Case Study: Internal Forces in a Truss Bridge

Scenario: A steel truss bridge carries a significant load from traffic. The engineers must ensure that the internal forces developed within the individual truss members do not exceed the material's capacity.
Analysis: When a heavy truck drives over the bridge, the external load creates a complex system of internal forces throughout the truss structure. Some members will stretch, indicating they are in tension, and other members will compress, meaning they are in compression. The internal force distributed continuously throughout the material's cross-section is what we define as stress. The structure maintains equilibrium by distributing these internal stresses through its nodes.

Case Study: Internal Forces in a Crane

Scenario: A tower crane lifts a heavy concrete block at a construction site.
Analysis: As the crane lifts the block, the steel cable suspending it experiences an immense internal tensile force trying to pull it apart. Simultaneously, the vertical mast of the crane experiences internal compressive forces pushing down on it, as well as bending forces. Understanding these internal forces is critical because if the internal force (stress) exceeds the material's failure limit, the cable could snap or the mast could buckle, leading to a catastrophic failure.

Basic Tensile Stress Calculation

A steel rod with a circular cross-section of radius 10 mm is subjected to a tensile force of 50 kN. Determine the normal stress in the rod.

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Intermediate Normal Stress Calculation

A hollow bronze cylinder with an outer diameter of 50 mm and an inner diameter of 30 mm carries an axial compressive load of 120 kN. Calculate the normal stress in the cylinder.

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Advanced Normal Stress: Two Materials

An aluminum tube is rigidly attached between a bronze rod and a steel rod. Axial loads are applied at the positions indicated. Determine the maximum normal stress in the assembly if the cross-sectional areas are: Bronze (Ab=400 mm2A_b = 400\text{ mm}^2), Aluminum (Aa=600 mm2A_a = 600\text{ mm}^2), and Steel (As=300 mm2A_s = 300\text{ mm}^2). The loads are: P1=20 kNP_1 = 20\text{ kN} pulling the bronze to the left, P2=15 kNP_2 = 15\text{ kN} pulling the connection of bronze/aluminum to the right, and P3=10 kNP_3 = 10\text{ kN} pulling the connection of aluminum/steel to the right. The steel is attached to a wall on the right.

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Basic Single Shear Stress Calculation

A single bolt connects two plates and is pulled by a force P=30 kNP = 30\text{ kN}. If the bolt has a diameter of 16 mm16\text{ mm}, determine the shear stress in the bolt.

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Intermediate Double Shear Stress Calculation

A bolt connects three plates. The inner plate is pulled with a force of 40 kN40\text{ kN}, while the two outer plates resist the force equally. If the bolt diameter is 12 mm12\text{ mm}, determine the shear stress in the bolt.

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Advanced Shear Stress Calculation

A circular punch 20 mm20\text{ mm} in diameter is used to punch a hole through a 10 mm10\text{ mm} thick steel plate. If the force required to punch the hole is 250 kN250\text{ kN}, what is the maximum shear stress in the plate?

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Basic Bearing Stress Calculation

A 20 mm20\text{ mm} diameter bolt connects two steel plates, each 15 mm15\text{ mm} thick. A tensile load of 45 kN45\text{ kN} is applied to the connection. Determine the bearing stress between the bolt and the plate.

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Intermediate Bearing Stress Calculation

A square column 300 mm300\text{ mm} on each side rests on a concrete footing 1.2 m×1.2 m1.2\text{ m} \times 1.2\text{ m}. If the load on the column is 800 kN800\text{ kN}, calculate the bearing stress between the column and the footing, and the bearing stress on the soil beneath the footing.

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Advanced Bearing Stress: Multiple Bolts

A lap joint uses four 16 mm16\text{ mm} bolts to connect two 12 mm12\text{ mm} thick plates. The joint transmits a load of 150 kN150\text{ kN}. Calculate the average bearing stress on the bolts.

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Basic Allowable Stress Calculation

A structural steel rod has an ultimate tensile strength of 400 MPa400\text{ MPa}. If the required Factor of Safety is 2.52.5, determine the allowable working stress.

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Intermediate Allowable Stress Design

A solid circular rod must carry a tensile load of 60 kN60\text{ kN}. The material has a yield strength of 250 MPa250\text{ MPa}. Using a Factor of Safety of 2.02.0 against yielding, calculate the required diameter of the rod.

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Advanced Allowable Stress: Design Choice

Two plates are to be joined by a single bolt. The applied load is 50 kN50\text{ kN}. The allowable shear stress for the bolt material is 100 MPa100\text{ MPa} and the allowable bearing stress for the plate material is 150 MPa150\text{ MPa}. The plates are 10 mm10\text{ mm} thick. What is the minimum required bolt diameter to satisfy both shear and bearing constraints?

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